Object#send and blocks/procs

[Mehr, Assaph (Assaph)]

Hi Guys,

I started to write this email as a question, but figured the answer in
the middle...
So now I want to know if there's any problem with the code below, if
there is any performance hit or if there's a simpler way to turn Procs
back into blocks.

The question is how do I #send a method to an object with an attached
proc (not block)? The simplest way to reproduce is:

prc = lambda{ |a| a.upcase }
puts "aaa".sendgsub, /./) # how do I pass prc as the block to
gsub?

Solution:

puts "aaa".sendgsub, /./) { |x| prc[x] }

i.e. I have wrapped my Proc object within a block. Some interspersing of
'*' may be required for multiple params, as Markus pointed out in
another thread.


Cheers,
Assaph

 

[Gavin Sinclair]

prc = lambda{ |a| a.upcase }
puts "aaa".sendgsub, /./) # how do I pass prc as the block to gsub?

Try this:

puts "aaa".sendgsub, /./, &prc)

Cheers,
Gavin

 

[George Ogata]

Hi Guys,

I started to write this email as a question, but figured the answer in
the middle...
So now I want to know if there's any problem with the code below, if
there is any performance hit or if there's a simpler way to turn Procs
back into blocks.

The question is how do I #send a method to an object with an attached
proc (not block)? The simplest way to reproduce is:

prc = lambda{ |a| a.upcase }
puts "aaa".sendgsub, /./) # how do I pass prc as the block to
gsub?

Solution:

puts "aaa".sendgsub, /./) { |x| prc[x] }

puts 'aaa'.sendgsub, /./, &prc)