opening a file

[Tim Hanson]

Using linux and Python 2.6, learning how to work with files from a Windows
oriented textbook:

This works:
infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')

This doesn't:
infile=open('~/prog/py_modules/this_is_a_test','r')

Can't I work with files using Unix expressions?

 

[Nobody]

This works:
infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')

This doesn't:
infile=open('~/prog/py_modules/this_is_a_test','r')

Can't I work with files using Unix expressions?

The argument is treated literally, just like C's fopen() etc. If you want
substitions, you have to perform them explicitly, e.g.:

infile=open(os.path.expanduser('~/prog/py_modules/this_is_a_test'),'r')