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def5
Hi,
what make this <<= operator ?
Code:
UCHAR x = 0 ;
x <<=6 ;
Thanks
what make this <<= operator ?
Code:
UCHAR x = 0 ;
x <<=6 ;
Thanks
Its like when you write x += 2 is the same as x = x + 2what make this <<= operator ?
Code:
UCHAR x = 0 ;
x <<=6 ;
Hi,
what make this <<= operator ?
Code:
UCHAR x = 0 ;
x <<=6 ;
Brian said:It is the same as writing: x = x << 6;
But its easier to optimize for the compiler
The second statement is extremely dubious. I can't
imagine any compiler that would care.
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