A
Aman
Hi,
please consider the following prog (SunOS 5.8,g++ compiler)
when I ran it through the debugger , I found that the program doesn't
output till either the "\n" or the exit .
(debugger ..Single stepping until exit from function _start ...)
what does reaching exit or \n have to do with cout or ostream_iterator
?
#include <iostream>
#include <string>
#include <iterator>
using namespace std ;
int main()
{
ostream_iterator<string> out(cout , " ") ;
*out ="hello" ;
out++ ;
*out = "world" ;
out++ ;
*out = "\n" ;
out++ ;
*out = "again" ;
}
regards,
please consider the following prog (SunOS 5.8,g++ compiler)
when I ran it through the debugger , I found that the program doesn't
output till either the "\n" or the exit .
(debugger ..Single stepping until exit from function _start ...)
what does reaching exit or \n have to do with cout or ostream_iterator
?
#include <iostream>
#include <string>
#include <iterator>
using namespace std ;
int main()
{
ostream_iterator<string> out(cout , " ") ;
*out ="hello" ;
out++ ;
*out = "world" ;
out++ ;
*out = "\n" ;
out++ ;
*out = "again" ;
}
regards,