passing *args "recursively"

[Guillermo]

Hi,

This must be very basic, but how'd you pass the same *args several
levels deep?


def func2(*args)

print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?

def func1(*args):

print args # (1, 2, 3)
func2(args)

func1(1,2,3)

Thanks!

Guillermo

 

[Matimus]

Hi,

This must be very basic, but how'd you pass the same *args several
levels deep?

def func2(*args)

print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?

def func1(*args):

print args # (1, 2, 3)
func2(args)

func1(1,2,3)

Thanks!

Guillermo

def func1(*args):
print args
func2(*args) # don't forget the '*'

Matt

 

[Gary Duzan]

Hi,

This must be very basic, but how'd you pass the same *args several
levels deep?


def func2(*args)

print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?

def func1(*args):

print args # (1, 2, 3)
func2(args)

func2(*args) # <<<<<<======

func1(1,2,3)

Gary Duzan
Motorola H&NM

 

[Mikael Olofsson]

This must be very basic, but how'd you pass the same *args several
levels deep?

def func2(*args)
print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?

def func1(*args):
print args # (1, 2, 3)
func2(args)

func1(1,2,3)

func2(*args)

Thats all. See
http://docs.python.org/tut/node6.html#SECTION006740000000000000000

/MiO

 

[Mikael Olofsson]

This must be very basic, but how'd you pass the same *args several
levels deep?

def func2(*args)
print args # ((1, 2, 3),)
# i want this to output (1, 2, 3) as func1!
# there must be some better way than args[0]?

def func1(*args):
print args # (1, 2, 3)
func2(args)

func1(1,2,3)

func2(*args)

Thats all. See
http://docs.python.org/tut/node6.html#SECTION006740000000000000000

That was a bit unclear. You should use func2(*args) when you call the
function.

/MiO