pointer cast

[Carlos F.]

Hi everyboy, somebody could tell me what meen the following cast:

a = (struct foo 8) b
c = int (func) (int)

Thanks

Carlos

 

[Christopher Benson-Manica]

a = (struct foo 8) b

If you meant (struct foo *) b, it's pretty self explanatory - cast b
to a foo pointer and assign it to a. Whether it results in
well-defined behavior or not depends on what a and b are declared as
and what's happened prior to the line in question.

c = int (func) (int)

Depends on what func is, and it's probably illegal anyway unless func
is an obfuscated macro. Post more code.

 

[Karthik]

Hi everyboy, somebody could tell me what meen the following cast:

a = (struct foo 8) b

Did u mean -
a = (struct foo *) b

Then you are casting pointer to type b to pointer to type a.

c = int (func) (int)

Not sure with this syntax .. Do you want to check that ?

 

[CBFalconer]

Hi everyboy, somebody could tell me what meen the following cast:

a = (struct foo 8) b

This is a syntax error.

c = int (func) (int)

If func exists both as a functional macro, and as a callable
function, this forces the actual function to be called. The macro
can only be called by "func(" which this is not.