pointer value

[JD]

int (*a)[10];
a++;
what will be the value of a?

 

[Michael Mair]

int (*a)[10];
a++;
what will be the value of a?

As always with ++ on a pointer:
(unsigned char *)a + 1*sizeof *a

As a points to array 10 of int, sizeof *a == 10 * sizeof (int).

As you have not initialised the pointer, the behaviour is
undefined.

Cheers
Michael

 

[Emmanuel Delahaye]

JD wrote on 30/07/05 :

int (*a)[10];
a++;
what will be the value of a?

a + 1

--
Emmanuel
The C-FAQ: http://www.eskimo.com/~scs/C-faq/faq.html
The C-library: http://www.dinkumware.com/refxc.html

"Clearly your code does not meet the original spec."
"You are sentenced to 30 lashes with a wet noodle."
-- Jerry Coffin in a.l.c.c++

 

[CBFalconer]

int (*a)[10];
a++;
what will be the value of a?

You answer this by considering what a is. It is a pointer to an
array of 10 ints. Since it is uninitialized, incrementing it (or
dereferencing it) results in undefined behavior.