Possible bug in ruby interpreter

[pp]

Hi there,

I found that the expression:

1*(rand (1) + 1)

will often evaluate to 0. Eliminating the space between rand and
( makes the problem go away. Is this a bug?

-pp

ruby 1.8.5 (2006-12-25 patchlevel 12) [i686-darwin8.8.2]

 

[Robert Klemme]

Hi there,

I found that the expression:

1*(rand (1) + 1)

will often evaluate to 0. Eliminating the space between rand and
( makes the problem go away. Is this a bug?

I'm afraid, the bug is in your keyboard or further up the "invocation"
chain.

rand (1) + 1 is parsed as rand( 1 + 1 ) which sometimes will evaluate
to 0. Method brackets need to appear directly after the identifier.

robert