preincrement

[prasoonthegreat]

int main( )
{
int i=1;
++i = 5;
}

Will the above code show Undefined Behaviour????
The value of i is changing only once between two sequence points or
twice??/???

I think twice,first after the increment and second after
assignment......but 5 will be assigned to incremented i in any
circumstances .....

So will it invoke UB???

 

[Neelesh]

int main( )
{
   int i=1;
  ++i = 5;

}

Will the above code show Undefined Behaviour????
The value of i is changing only once between two sequence points or
twice??/???

almost the same question was posted just a few hours ago, please have
a look at that
http://groups.google.com/group/comp.lang.c++/browse_thread/thread/710ffcc66a03b843

I think twice,first after the increment and second after
assignment......but  5 will be assigned to incremented i in any
circumstances .....

Changing value of a variable more than once between two consecutive
sequence points results in undefined behaviour.