print an array by C++

[sofin]

I have a 2-dimension array whose format can be either float or
integer.
I would like to write a function to print out this array no matter its
format is float or integer.
I don't know how to pass the argument because the format of the array
could be float or int?

void function(float array, row, col){
^^^^^^
Could be also int
int i=0;
int j=0;

for(j=0;j<col;j++){
for(i=0;i<row;i++){
cout << array[j] << endl;
}
}
}

 

[ctrucza]

I have a 2-dimension array whose format can be either float or

integer.
I would like to write a function to print out this array no matter its
format is float or integer.

First off: you should post compilable code.

You should write a function template:

template<class T>
void foo(T* a, int row, int col)
{
for(int j=0;j<col;j++)
{
for(int i=0;i<row;i++)
{
cout << a[i*col+j] << endl;
}
}
}

int main()
{
float f[4] = {0.1f,0.2f,0.3f,0.4f};
int n[4] = {42, 43, 44, 45};

foo<int>(n,2,2);
foo<float>(f,2,2);
}

I don't know how to pass the argument because the format of the array
could be float or int?

void function(float array, row, col){
                 ^^^^^^
                  Could be also int
int i=0;
int j=0;

   for(j=0;j<col;j++){
       for(i=0;i<row;i++){
             cout << array[j] << endl;
       }
   }

}

 

[sofin]

If I put foo function in foo.c and use main.c to call foo, when g++ -0
main.o foo.o ===>
it appears that "undefined reference to foo".
I test if foo is a normal function without template<class >, there is
no such a problem.
Can someone tell me why?
Thanks.

First off: you should post compilable code.

You should write a function template:

template<class T>
void foo(T* a, int row, int col)

The OP's array is apparently two-dimensional. It might be better to use
that in the declaration:

{

And then you have N and M for the counters to run up to, instead of
passing the arguments, which can easily be wrong.

for(int j=0;j<col;j++)
{
for(int i=0;i<row;i++)
{
cout << a[i*col+j] << endl;
}
}
}

int main()
{
float f[4] = {0.1f,0.2f,0.3f,0.4f};
int n[4] = {42, 43, 44, 45};

foo<int>(n,2,2);
foo<float>(f,2,2);
}

I don't know how to pass the argument because the format of the array
could be float or int?
void function(float array, row, col){
^^^^^^
Could be also int
int i=0;
int j=0;
for(j=0;j<col;j++){
for(i=0;i<row;i++){
cout << array[j] << endl;
}
}
}

V

 

[Alan Woodland]

If I put foo function in foo.c and use main.c to call foo, when g++ -0
main.o foo.o ===>
it appears that "undefined reference to foo".
I test if foo is a normal function without template<class >, there is
no such a problem.
Can someone tell me why?
Thanks.

See:
http://www.parashift.com/c++-faq-lite/templates.html#faq-35.13

Alan