printing with variable length of list

[les ander]

Hi,
suppose I have a list
d=[1.2 , 31.1, 1.001]
in general i will not know the size of d
however, I would like to print them out nicely in the row format
such as:
print "%-10f "* len(d) % d

however, the above line does not work--python says that float
argument is required.
So i did
print "%-10s "* len(d) % map(str,d)
But now I get:
TypeError: not enough arguments for format string

please help
thanks

 

[Riccardo Galli]

Hi,
suppose I have a list
d=[1.2 , 31.1, 1.001]
in general i will not know the size of d
however, I would like to print them out nicely in the row format
such as:
print "%-10f "* len(d) % d

however, the above line does not work--python says that float
argument is required.

You need a tuple, not a list
print "%-10f "* len(d) % tuple(d)

Riccardo

--
-=Riccardo Galli=-

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s~ ``
~@. ideralis Programs
.. ol
`**~ http://www.sideralis.net

 

[Alex Martelli]

Hi,
suppose I have a list
d=[1.2 , 31.1, 1.001]
in general i will not know the size of d
however, I would like to print them out nicely in the row format
such as:
print "%-10f "* len(d) % d

tuple(d) is one possibility, as Riccardo pointed out. A small loop
might also be nice, and conceptually simple:

for item in d:
print '%-10f'%item,
print

the comma at the end stops print from emitting a newline, and a space is
used between item; the print at the end ends the line.


Alex

 

[Dan Bishop]

Hi,
suppose I have a list
d=[1.2 , 31.1, 1.001]
in general i will not know the size of d
however, I would like to print them out nicely in the row format
such as:
print "%-10f "* len(d) % d

Try:

print "%-10f " * len(d) % tuple(d)

 

[Peter Otten]

suppose I have a list
d=[1.2 , 31.1, 1.001]
in general i will not know the size of d
however, I would like to print them out nicely in the row format
such as:
print "%-10f "* len(d) % d

Here is a functional variant:

d = [1.2 , 31.1, 1.001]
def format(f):

.... return "%-10f" % f
....1.200000 31.100000 1.001000

which can be simplified to
1.200000 31.100000 1.001000

if you like. I'm assuming that the trailing space in your approach was
accidental.

Peter