Problem calling Java method in XSLT (Xalan)

[Robbie Baldock]

Hi -

I'm a bit of a newbie to the world of XSLTs but am trying to call a Java method on a parameter passed into an XSLT but
am having problems.

I've stripped the XSLT down to its bare bones:

<xsl:stylesheet
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslaram name="requestContext"/>
<xsl:variable name="site" select="java:$requestContext.getCurrentSite()"/>
</xsl:stylesheet>

But xsl:variable line produces the error:

"A node test that matches either NCName:* or QName was expected."

Can anyone spot where I'm going wrong?

Thanks for any suggestions.


Robbie

 

[David Carlisle]

Hi -

I'm a bit of a newbie to the world of XSLTs but am trying to call a Java method on a parameter passed into an XSLT but
am having problems.

I've stripped the XSLT down to its bare bones:

<xsl:stylesheet
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslaram name="requestContext"/>
<xsl:variable name="site" select="java:$requestContext.getCurrentSite()"/>
</xsl:stylesheet>

But xsl:variable line produces the error:

"A node test that matches either NCName:* or QName was expected."

Can anyone spot where I'm going wrong?

Thanks for any suggestions.


Robbie

function names in xslt (as in C or java o most other languages) are
single tokens you can't use an expression to generate the name and you
can't replace part of teh name by a variable reference.

so you can use java:foo(....) if you have a method foo available but you
can't generate a funtion name from a parameter (unless you use an
evaluet() extension function taht parses a string as an Xpath
expression.

David

 

[Stanimir Stamenkov]

/Robbie Baldock/:

<xsl:variable name="site" select="java:$requestContext.getCurrentSite()"/>

Did you mean:

<xsl:variable
name="site">java:$requestContext.getCurrentSite()</xsl:variable>

or (the same):

<xsl:variable name="site"
select="'java:$requestContext.getCurrentSite()'"/>

?

 

[Stanimir Stamenkov]

/Stanimir Stamenkov/:

/Robbie Baldock/:

missed that one...

Did you mean:

<xsl:variable name="site">java:$requestContext.getCurrentSite()</xsl:variable>

or:

<xsl:variable name="site">java:<xsl:value-of
select="$requestContext"/>.getCurrentSite()</xsl:variable>

I think it should be the same:

<xsl:variable name="site" select="concat('java:', $requestContext,
'.getCurrentSite()'"/>

But reading through the David Carlisle's reply I realize you may be
trying something different.

 

[Robbie]

so you can use java:foo(....) if you have a method foo available but you
can't generate a funtion name from a parameter (unless you use an
evaluet() extension function taht parses a string as an Xpath
expression.

OK, I think I understand...!

Thanks for the info.


Robbie

 

[Robbie]

But reading through the David Carlisle's reply I realize you may be
trying something different.

I shall try your various suggestions.

Thanks for the response.


Robbie

 

[Frank Meyer]

hi,

I've stripped the XSLT down to its bare bones:

<xsl:stylesheet
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslaram name="requestContext"/>
<xsl:variable name="site" select="java:$requestContext.getCurrentSite()"/>
</xsl:stylesheet>

you have to use select="java:getCurrentSite($requestContext)"

regards
frank

 

[Ram C]

requestContext Problem in XSL

Hi All ...

Even I gotta problem using the requestContext as xslaram - and can anyone tell exactly what is the use of declaring it as a xslaram instead of a normal xsl:variable ?

From where does the XSL processor get the requestContext Object ? should anything be done explicitly to get that object
or
just declaring it as a xslaram will do ... ?

Waiting for solution,

Thanks,
Ram C

Hi -

I'm a bit of a newbie to the world of XSLTs but am trying to call a Java method on a parameter passed into an XSLT but
am having problems.

I've stripped the XSLT down to its bare bones:

<xsl:stylesheet
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xslaram name="requestContext"/>
<xsl:variable name="site" select="java:$requestContext.getCurrentSite()"/>
</xsl:stylesheet>

But xsl:variable line produces the error:

"A node test that matches either NCName:* or QName was expected."

Can anyone spot where I'm going wrong?

Thanks for any suggestions.


Robbie