public and private members of the module

[Lev Elblert]

Acording to documentation the are 2 ways to "hide" functions, data
inside the module:

1. __all__ list
2. starting "hiden" names with underscore.

None of these methods does not work:

############################################
#File: foo.py
import sys
__all__ = ['B']
def A():
print "In A"
def B():
print "In B"
def _C():
print "In _C"
############################################
#File: a.py
import foo
print dir(foo)
foo.A()
foo.B()
foo._C()

Running a.py produces this output:

['A', 'B', '_C', '__all__', '__builtins__', '__doc__', '__file__',
'__name__', 'sys']
In A
In B
In _C

Can somebody explain this?

I'm working on Windows Python 2.3


Thanks in advance

 

[Dennis Lee Bieber]

Acording to documentation the are 2 ways to "hide" functions, data
inside the module:

1. __all__ list
2. starting "hiden" names with underscore.

None of these methods does not work:

Forgive me, but your double negative phrase is equal to "all of
these methods do work" <G>

And, they probably do... What you missed is that the "hide" only
applies to the use of

from module import *

The * will only pick up those in the __all__ list, or in on
__all__ then those not beginning with _

--

 

[Dennis Lee Bieber]

The * will only pick up those in the __all__ list, or in on

Pardon -- "in on" is supposed to be "if no"

__all__ then those not beginning with _

Obviously it was time for me to go to bed...

--