Python - limiting input to certain characters

[alicegoody]

I am trying to limit a user's input to either the letter y or n. I am using this code. However, even when I enter n or y it still loops. I would appreciate someone letting me know where I have gone wrong! Thank you very much.

while parking_pass != 'n' or 'y':
print ("Error Contains illegal characters")
print("Would you like a free parking pass y/n?")
parking_pass = str(input())
else:
print("Your parking pass has been added to your order")

 

[Moorcam]

I am trying to limit a user's input to either the letter y or n. I am using this code. However, even when I enter n or y it still loops. I would appreciate someone letting me know where I have gone wrong! Thank you very much.

while parking_pass != 'n' or 'y':
print ("Error Contains illegal characters")
print("Would you like a free parking pass y/n?")
parking_pass = str(input())
else:
print("Your parking pass has been added to your order")

The or 'y' part is always true, which means the loop will not terminate as expected.
Check if parking_pass is not equal to both 'n' and 'y'. The condition should use the and operator instead of or.
Hope this helps.

 

[menator01]

while parking_pass not in ('y','n'):
    # Do stuff

 

[VBService]

BTW,

parking_pass = str(input())

'''
   when you write str(input()), you are performing an unnecessary type conversion 
   because the result of input() is already of type str.
'''
parking_pass = input()

user friendly

while parking_pass not in ('y', 'Y', 'n', 'N'):

# or
    
while parking_pass.lower() not in ('y', 'n'):

 

[WhiteCube]

The interesting thing to me about this error is that when read out loud, while parking_pass != 'n' or 'y' sounds right. Its the way an english speaker would phrase it.

Makes me wonder what other statements read perfectly fine, but are actually completely wrong.

The other thing is, why is there an else: in your while statement?