Regular expression

[Back9]

Hi,

I have a string like this:
0x340x5A0x9B0xBA
I want to extract 0x from the string but the first one.

How I can use re for this case?

The string size will vary.

TIA

 

[ilvecchio]

 Hi,

I have a string like this:
0x340x5A0x9B0xBA
I want to extract 0x from the string but the first one.

How I can use re for this case?

The string size will vary.

TIA

Maybe the easy way is something like this:

m = re.match('(0x)(.*)','0x340x5A0x9B0xBA')
m.groups()[1]

Terenzio

 

[Back9]

 Hi,

I have a string like this:
0x340x5A0x9B0xBA
I want to extract 0x from the string but the first one.

How I can use re for this case?

The string size will vary.

TIA

Maybe the easy way is something like this:

m = re.match('(0x)(.*)','0x340x5A0x9B0xBA')
m.groups()[1]

Terenzio

I mean the result should be like this:
0x345A9BBA

 

[Jon Clements]

Maybe the easy way is something like this:

m = re.match('(0x)(.*)','0x340x5A0x9B0xBA')
m.groups()[1]

Terenzio

I mean the result should be like this:
0x345A9BBA

Something like: re.sub(r'\B(0x)', '', s)


hth, Jon.

 

[J. Cliff Dyer]

Don't use regular expressions for that.

s = '0x340x5A0x9B0xBA'
return '0x' + ''.join(s.split('0x'))

 

[Terry Reedy]

Don't use regular expressions for that.

s = '0x340x5A0x9B0xBA'
return '0x' + ''.join(s.split('0x'))
or

>>> '0x'+s[2:].replace('0x','')

'0x345A9BBA'

Take your pick, you should learn and understand both.

 

[Anthra Norell]

Hi,

I have a string like this:
0x340x5A0x9B0xBA
I want to extract 0x from the string but the first one.

How I can use re for this case?

The string size will vary.

TIA

Unless the use of a regular expression is a requirement I'd do it like this:

'0x%s' % s.split ('x', 1)[1].replace ('x', '')

Frederic