regulars expressions ?

[scott]

hi people !

<newbie>
i got some trouble with regular expressions
i need to split a string like this on the ',' character :

mystring = ""\test1, test2\", test, 42"

i wanna get something (a list) like this (3 elements) :
"test1, test2"
test
42

but the only thing i get is a list like this (4 elements) :
"test1"
"test2"
test
42

each element is separated by ',' but 1st element which is delimited by
'"' may contain ',' character inside.

so the regular expression i need is something like :
split each element using ',' delimiter but if ',' delimiter is included
between '"' please do not split
</newbie>

1st question is : does someone has understood the question ?
2nd question is : does someone has an answer ?

thanks people

scott

 

[Jaime Wyant]

Maybe, you need the csv module:

import csv
mystring = "\"test1, test2\", test, 42"

# The one argument to csv.reader is an iterable object
# You could use a file here...
csv_reader = csv.reader([mystring])

for line in csv_reader:
print line

['test1, test2', ' test', ' 42']

hth,
jw

 

[Jaime Wyant]

Doh - please note that csv.reader takes more than one argument - the
FIRST one is an iterable object.

jw

Maybe, you need the csv module:

import csv
mystring = "\"test1, test2\", test, 42"

# The one argument to csv.reader is an iterable object
# You could use a file here...
csv_reader = csv.reader([mystring])

for line in csv_reader:
print line

['test1, test2', ' test', ' 42']

hth,
jw

 

[Devan L]

re.findall(r'"?(.+?)"?(?:,|$)', yourtexthere)

 

[Devan L]

Oh, oops, sorry, that code doesn't respect the quotes.
Use this code:
re.findall(r'(".+?"|\S+)(?:,|$)', yourtexthere)