Retrieving a stacktrace from an exception object / forwarding an exception

[Samuel]

Hi,

I am trying to wrap a function that throws an exeption in such a way
that the stacktrace is logged into a file and the exception is
forwarded after that. For example:

-------------------
def my_func():
raise Exception("hello")

def wrapper():
try:
my_func()
except Exception, e:
f = open("logfile", 'a')
f.write(e.stacktrace())
raise e

wrapper() # should throw the exception with a stacktrace showing
my_func()

 

[Gabriel Genellina]

I am trying to wrap a function that throws an exeption in such a way
that the stacktrace is logged into a file and the exception is
forwarded after that. For example:

-------------------
def my_func():
raise Exception("hello")

def wrapper():
try:
my_func()
except Exception, e:
f = open("logfile", 'a')
f.write(e.stacktrace())
raise e

wrapper() # should throw the exception with a stacktrace showing
my_func()

- see the traceback module
<http://docs.python.org/lib/module-traceback.html>
- use a bare raise (not raise e); this reraises the active exception
without changing its context.

 

[alg]

Use the traceback module:

def log_exception():
"""This function will log the current exception's traceback
to logfile
"""
import traceback
f = open("logfile", 'a')
traceback.print_exc(32, f)
f.close()

def my_func():
raise Exception

def wrapper():
try:
my_func()
except Exception, e:
log_exception()
raise e

 

[Samuel]

Thanks, Guys, this works as expected.

-Samuel