Jeremy thanks so much for your help......it works.
could you please explain further how %r{(\(.*\)).*/(.*)'..(.*)}
captures the 3 interested part from the string......
I know you have explained but if you could kindly explain more with an
easy way I think it will help me to learn....
thanks again
Sure thing. Especially when you're learning about regular expressions
it really helps to start by breaking them down. You often have to do
that even when you're experienced but looking at someone else's work.
;-) Be aware that I'm going to gloss over quite a bit here, so you
still need to learn some basics.
We can break down this regexp into 5 parts:
(\(.*\)) <- The first capture
*/ <- Noise
(.*) <- The second capture
'.. <- More noise
(.*) <- The last capture
Anything within the unescaped parenthesis will be captured and assigned
to one of the $1, $2, etc. global variables. In the first capture, we
need to capture the literal parenthesis which appear in the string, so
we escape these with backslashes in order to remove their special
meaning to the regular expression engine. Then we want to slurp up any
text between the parenthesis, so we use ".*".
The first bit of noise absorbs the uninteresting bits of the string
which follow up to and including the forward slash. The * operator is
greedy and dot (.) matches any single character, so .* will match
everything including forward slashes. It only stops because we
specifically said that this chunk of the regexp must end with a forward
slash. Since it would be impossible to consume the last forward slash
and still match one more, this noise accumulation stops. It's not
within parenthesis, so it's not captured either.
The second capture cooperates with the following noise section. The
capture part would greedily consume everything much like the first noise
section; however, the second noise section requires that a single quote
be available to start it. There must be at least 1 single quote left in
the string, so the second capture stops when there is only 1 left in
this case.
The second noise section goes on to consume 2 more characters after the
single quote. This is because of the dot dot (..) in it. Each matches
1 of any single character.
Finally the last capture section is left to consume the rest of the
string exactly as the second capture would have done had nothing else
followed it in the regexp.
When building regexps, it's almost always a good idea to start small and
build up. I like using irb for this since it gives me rapid results.
You'll need more basics than I can provide here though if you want to
become proficient. Good luck!
-Jeremy
