Scanner input problem

[slayer_azure]

This is a simple program that I have written in Grade 12 Information
Technology, and we were instructed to do the following, which is to
ask the user to enter an integer, then call a method and asked a user
to enter their full name. Input is done using the methods from the
Scanner class of the java.util.* package. When I run the program, the
first part runs correctly and I enter a number but after that it calls
the name() method and prints "Enter FULL name: " but then the program
ends without giving me the chance to enter a name. What am I doing
wrong? Help will be appreciated.

import java.util.*;
public class test
{
static Scanner kbRead=new Scanner(System.in);
static String fname;
public static void main (String[]args)
{
System.out.println("Enter a number: ");
int num=kbRead.nextInt();
name();

}
public static void name()
{
System.out.print("Enter FULL name:");
fname=kbRead.nextLine();
}
}

 

[Andreas Leitgeb]

... When I run the program, the
first part runs correctly and I enter a number but after that it calls
the name() method and prints "Enter FULL name: " but then the program
ends without giving me the chance to enter a name.
int num=kbRead.nextInt();
fname=kbRead.nextLine();

When you entered the integer, you surely hit the Enter-key afterwards.
that line-end is not consumed through reading the integer, but it is
already entered by the time where you do the nextLine() call.

To verify this, enter:
42 Anonymous
in one line and press Enter afterwards.
It'll probably still not wait for a second return, but take
Anonymous as the name.

If you're sure, that you always press Enter directly after the
number, you can insert a (dummy) "kbRead.nextLine();" directly
after the nextInt(). Or you could check for an empty name, and
redo the nextLine() only in that case.

 

[slayer_azure]

When you entered the integer, you surely hit the Enter-key afterwards.
that line-end is not consumed through reading the integer, but it is
already entered by the time where you do the nextLine() call.

To verify this, enter:
  42 Anonymous
in one line and press Enter afterwards.
It'll probably still not wait for a second return, but take
Anonymous as the name.

If you're sure, that you always press Enter directly after the
number, you can insert a (dummy) "kbRead.nextLine();" directly
after the nextInt(). Or you could check for an empty name, and
redo the nextLine() only in that case.

Thanks it worked perfectly. Appreciate your help.