Sort dictionary

[Markus Franz]

Hi!

I have:

x = {'a':3, 'b':2, 'c':4}

How can I sort x by value? (I tried using sorted() with x.items() - but I
didn't get a dictionary as response.)

My second question:
How can I reduce the dictionary to 2 items (so delete everything after the
first two items)

Thanks in advance.

Best regards,
Markus

 

[Claudio Grondi]

Hi!

I have:

x = {'a':3, 'b':2, 'c':4}

How can I sort x by value? (I tried using sorted() with x.items() - but I
didn't get a dictionary as response.)

My second question:
How can I reduce the dictionary to 2 items (so delete everything after the
first two items)

Thanks in advance.

Best regards,
Markus

See my reply in de.comp.lang.python

Claudio

 

[=?iso-8859-1?q?Luis_M._Gonz=E1lez?=]

This function return a tuple of value-key pairs, sorted by value:
return sorted( [(v,k) for k,v in myDict.items()] )

If you want to get the first two value-key pairs:

sortByValue(x)[:2]

[(2, 'b'), (3, 'a')]

Hope this helps...
Luis

 

[=?iso-8859-1?q?Luis_M._Gonz=E1lez?=]

This function returns a tuple of value-key pairs, sorted by value:
return sorted( [(v,k) for k,v in myDict.items()] )

If you want to get the first two value-key pairs:

sortByValue(x)[:2]

[(2, 'b'), (3, 'a')]

Hope this helps...
Luis

 

[=?iso-8859-1?q?Luis_M._Gonz=E1lez?=]

You can't get a dictionary ordered by values, but you can get a list of
key-value pairs ordered by value:

def sortByValue(myDict):
x = sorted( [(v,k) for k,v in myDict.items()] )
return [(k,v) for v,k in x]

For getting only the first two pairs:

sortByValue(x)[:2]

Hope this helps...
Luis