source code of a function object

[Fernando Rodriguez]

Hi,

Is ti possible to get the source code of a given function object? O

TIA

 

[Erno Kuusela]

Hi,

Is ti possible to get the source code of a given function object? O

TIA

def dumps(obj, protocol=None, bin=None):
file = StringIO()
Pickler(file, protocol, bin).dump(obj)
return file.getvalue()

-- erno

 

[anton muhin]

Hi,

Is ti possible to get the source code of a given function object? O

TIA

I'm not an expert, but I'd say that mostly yes, however:

def foo():
pass

bar_code_block = compile('def bar(): pass', '<string>', 'exec')
exec bar_code_block

import inspect

assert 'foo' in locals()
print inspect.getsource(foo)

assert 'bar' in locals()
print inspect.getsource(bar)

Python2.3:
def foo():
pass

Traceback (most recent call last):
File "source.py", line 13, in ?
print inspect.getsource(bar)
File "D:\Python23\lib\inspect.py", line 549, in getsource
lines, lnum = getsourcelines(object)
File "D:\Python23\lib\inspect.py", line 538, in getsourcelines
lines, lnum = findsource(object)
File "D:\Python23\lib\inspect.py", line 408, in findsource
raise IOError('could not get source code')
IOError: could not get source code

Therefore, I'd suggest that you can get source code of functions that
are not created with eval/exec etc.

of course, you cannot get source code of C functions (e.g. most of
builtins, I suppose).

regards,
anton.