T
Thomas Philips
I attempt to open a writeable file inside some nested loops, and want
my program to terminate cleanly with an error message if it cannot
find the file's path (e.g. directory does not exist). So I write
try: outFile = file(outFileName, "w")
except IOError:
print "The output file",outFileName,"cannot be created."
_quit()
but when I run the code in IDLE, I get
The output file c:\python23\programs\Ford\PaLGUVMO20\PaLGUVMO20.91c
cannot be created.
Traceback (most recent call last):
File "C:\Python23\Programs\ford1.py", line 109, in -toplevel-
main()
File "C:\Python23\Programs\ford1.py", line 66, in main
_quit()
NameError: global name '_quit' is not defined
I've tried stop() instead of _quit(), with similar results. break does
not do the job - it just breaks out of the innermost loop and the
outer loops keep running. What's the fix?
Thomas Philips
my program to terminate cleanly with an error message if it cannot
find the file's path (e.g. directory does not exist). So I write
try: outFile = file(outFileName, "w")
except IOError:
print "The output file",outFileName,"cannot be created."
_quit()
but when I run the code in IDLE, I get
The output file c:\python23\programs\Ford\PaLGUVMO20\PaLGUVMO20.91c
cannot be created.
Traceback (most recent call last):
File "C:\Python23\Programs\ford1.py", line 109, in -toplevel-
main()
File "C:\Python23\Programs\ford1.py", line 66, in main
_quit()
NameError: global name '_quit' is not defined
I've tried stop() instead of _quit(), with similar results. break does
not do the job - it just breaks out of the innermost loop and the
outer loops keep running. What's the fix?
Thomas Philips