string extraction

[Navindra Umanee]

Hi,

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

Right now I'm doing:

string[/(\d*)\/*$/].delete('/')

But I've already matched the digit I want, so the delete is just
superfluous work. How can I extract the number without doing a
separate delete?

Thanks,
Navin.

 

[Eko Budi Setiyo]

Hi,

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

Right now I'm doing:

string[/(\d*)\/*$/].delete('/')

But I've already matched the digit I want, so the delete is just
superfluous work. How can I extract the number without doing a
separate delete?

Thanks,
Navin.

class String
def str_replace(what,with)
re = Regexp.new(Regexp.quote(what))
self.gsub(re) {with}
end

def str_ireplace(what,with)
re = Regexp.new(Regexp.quote(what), Regexp::IGNORECASE)
self.gsub(re) {with}
end
end

string='.///root/1068663688//1068824962/1068836207//1068932537///'

string = string.str_replace('///','')
string = string.str_replace('//','/')
temp = string.split('/')
return temp[4]

regards
Eko

 

[Martin S. Weber]

Hi,

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

string[%r|/(\d+)/+$|, 1] ?

hth,

-Martin

 

[David A. Black]

Hi --

Hi,

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

Right now I'm doing:

string[/(\d*)\/*$/].delete('/')

But I've already matched the digit I want, so the delete is just
superfluous work. How can I extract the number without doing a
separate delete?

You can use a negative-width lookahead:

string[/(\d*)(?=\/*$)/]


David

 

[David A. Black]

Hi -

Hi --

Hi,

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

Right now I'm doing:

string[/(\d*)\/*$/].delete('/')

But I've already matched the digit I want, so the delete is just
superfluous work. How can I extract the number without doing a
separate delete?

You can use a negative-width lookahead:

Sorry, too little coffee. That's zero-width lookahead


David

 

[Navindra Umanee]

string[%r|/(\d+)/+$|, 1] ?

Exactly what I was looking for, thanks. The zero-width positive
lookahead is also interesting.

str[regexp, fixnum]

Is there a similar way to combine and use different matched groups
instead of being restricted to a fixnum? Say instead of just \1 you
had a match for \1 and \2 and you wanted the output string to be \2 \1

"byru"[/(by)(ru)/, \2\1]

should output "ruby".

Thanks,
Navin.

 

[Bertram Scharpf]

Hi,

Am Samstag, 29. Jan 2005, 16:05:57 +0900 schrieb Navindra Umanee:

I have strings of the form:

string='.///root/1068663688//1068824962/1068836207//1068932537///'

Basically, I want to extract the last number in the string.

string[/(\d*)\/*$/].delete('/')

But I've already matched the digit I want, so the delete is just
superfluous work. How can I extract the number without doing a
separate delete?

Maybe you simply need to say

string[/\d+\/*$/].to_i

that doesn't mind trailing slashes.

Bertram