strip method

[Amasa Masiarek]

s = <<EOS
a1\t b1
a2\tb2
EOS

s.each{|e|
a = e.strip.split("\t")
p a[1]
}

output:
" b1"
"b2"

expected output:
"b1"
"b2"

What is wrong?

 

[Amasa Masiarek]

This works fine ...

s.each{|e|
a = e.gsub(' ','').split("\t")
p a[1]
}

 

[Rick DeNatale]

s = <<EOS
a1\t b1
a2\tb2
EOS

s.each{|e|
a = e.strip.split("\t")
p a[1]
}

output:
" b1"
"b2"

expected output:
"b1"
"b2"

What is wrong?

k$ qri String#strip
----------------------------------------------------------- String#strip
str.strip => new_str
------------------------------------------------------------------------
Returns a copy of str with leading and trailing whitespace removed.

Leading and trailing doesn't mean internal. So:

"a1\t b1".strip #=> "a1\t b1"

 

[David A. Black]

Hi --

s = <<EOS
a1\t b1
a2\tb2
EOS

s.each{|e|
a = e.strip.split("\t")
p a[1]
}

output:
" b1"
"b2"

expected output:
"b1"
"b2"

What is wrong?

Your expectation Sorry, I couldn't resist.

strip removes space on the right and left. If you start with
"a1\t b1\n", the stripped version is "a1\t b1". If you split that on
\t, you get "a1" and " b1". At no point have you removed the middle
space.


David

--
Rails training from David A. Black and Ruby Power and Light:
INTRO TO RAILS June 9-12 Berlin
ADVANCING WITH RAILS June 16-19 Berlin
INTRO TO RAILS June 24-27 London (Skills Matter)
See http://www.rubypal.com for details and updates!

 

[William James]

s = <<EOS
a1\t b1
a2\tb2
EOS

s.each{|e|
a = e.strip.split("\t")
p a[1]

}

output:
" b1"
"b2"

expected output:
"b1"
"b2"

What is wrong?

"

a1\t b1
a2\tb2


".strip.each{|x|
a = x.split("\t").map{|s| s.strip }
p a.last
}

 

[Gordon Thiesfeld]

s = <<EOS
a1\t b1
a2\tb2
EOS

s.each{|e|
a = e.strip.split("\t")
p a[1]

}

output:
" b1"
"b2"

expected output:
"b1"
"b2"

What is wrong?

"

a1\t b1
a2\tb2


".strip.each{|x|
a = x.split("\t").map{|s| s.strip }
p a.last
}

Or split on whitespace instead of on tabs alone.

s.each{|e|
a = e.split("\s")
p a[1]
}