struct ?

[tvn007]

I am working on the data struc. below:
is there way I can abbrev. the expression below to avoid long
expression.
Thanks......
///////////////////////////////////////////////////////////////////////////////////
#include <iostream>
#include <string>
#include <fstream>
#include <sstream>
using namespace std;
const int MAX=50;
struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;

int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);

/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;
//////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
ptrstudent++;
}
}

 

[Ron Natalie]

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;

istream& operator>> (istream& is) (
is >> bypassed;
is >> name
is >> midterm;
is >> quiz
is >> final;
is >> testname;
return is;
}

}student[MAX],*ptrstudent;


int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);

/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////


anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

anyname >> *ptrstudent;

 

[Richard Herring]

istream& operator>> (istream& is) (

If its _left_ operand is to be an istream, this can't be a member
function of Record_info. It has to be a non-member function with two
arguments.

friend istream & operator>>(istream & is, Record_info & rec) {

is >> bypassed;

is >> rec.bypassed; // etc.

is >> name
is >> midterm;
is >> quiz
is >> final;
is >> testname;
return is;
}

}student[MAX],*ptrstudent;


int main (void){
ptrstudent = student;
ifstream in ("test2.txt");
string line;
string line2;
char buffer[40];
while (getline(in,line)){
if (line.find("#")!=string::npos)continue ;
istringstream anyname(line);
/////////// HOW CAN I ABBREV. EXPRESSION BELOW ?
////////////////////////////////////////


anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;

anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

anyname >> *ptrstudent;

///////////////////////////////////////////////////////////////////////
///////////////////////////////////////////////////////
ptrstudent++;
}
}

 

[tvn007]

I am not sure if it will work since I am using struct array and
pointer.

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;
ptrstudent = student;

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;


anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

 

[Jakob Bieling]

I am not sure if it will work [..]

Have you tried it?

 

[Richard Herring]

I am not sure if it will work

Not sure if _what_ will work? Please quote some context.

since I am using struct array and
pointer.

I don't think that's relevant. Fundamentally you want to implement
operator>>(istream&, Record_info &). If the Record_info happens to be an
array element or the target of a pointer it makes no difference.

struct Record_info {
string bypassed;
string name;
int midterm;
double quiz;
double final;
string testname;
}student[MAX],*ptrstudent;
ptrstudent = student;

anyname>>ptrstudent->bypassed>>ptrstudent->name>>ptrstudent->midterm;


anyname>>ptrstudent->quiz>>ptrstudent->final>>ptrstudent->testname;

anyname >> *ptrstudent;