muser said:
I'am having problem with the following:
rec1len = strlen(temp1);
temp1 is a character array, multi dimensional array.
it has been initialised as char temp1[12][104];
int rec1len.
error for this message: C:\Program Files\Microsoft Visual
Studio\MyProjects\Valid\Zenith124\Zenith.cpp(162) : error C2664:
'strlen' : cannot convert parameter 1 from 'char [12][104]' to 'const
char *'
can anyone help please.
That's not how strlen() works. strlen() works with char*s, not character
arrays.
If you had something like this:
char temp1[12];
It would work if you took the address of that:
rec1len = strlen(&temp1);
But because you have a multidimensional array, you cannot do that. What I'm
assuming you're doing is having 104 "strings" which are up to 12 characters
long (or 12 strings up to 104 characters long). Note I say string here
meaning the C style string, that is, a char*. Perfectly legal in C++ but a
little bit harder to work with. If you must keep it char[12][104] and just
wanted to add up all of the string lengths, here's what you'll want to do:
rec1len = 0;
for (int x = 0; x < 104; x++)
rec1len += strlen(&temp1[x]);
I'm pretty sure that's how it works. I may have the two indexes mixed up,
but you're only supposed to put one of them down. I think it's the second
one, and then take the address of the first. Anyone else there please feel
free to pipe in if I got it wrong.
BTW: In C++, we have an easier way of dealing with strings, the aptly named
string class. First off, you'll need to
#include <string>
using namespace std; // if you haven't already
string temp1[104]; // make 104 strings
And now to add up the lengths, you could
rec1len = 0;
for (int x = 0; x < 104; x++)
rec1len += temp1[x].length();
Code Not Compiled
