Zach said:
#include <stdio.h>
#include <math.h>
int i=0, j=0, *z=0;
double tanjent=0.0;
1> void main(int *)
{
for(;
{
2> tanjent[&z] = sin(i) / cos (j);
3> *z=&z+1
}
4> printf(tanjent[k],"%d);
5> return &z;
}
1> main returns int, and has parameters of type int and char**
2> attempt to index NULL, doomed.
2> sin(0) / cos(0) == 0 / 1 == 0
3> attempt to store a pointer in an int. No final semi.
4> Bad arguments to printf, and unterminated string. k undeclared.
5> returning a pointer in place of an int.
The "for(;
" line is correct, as are the isolated braces. So I
would say it falls a tad short of perfection. Your compiler should
have showed these up.
[1] c:\c\junk>cc junk.c
junk.c:8: warning: return type of `main' is not `int'
junk.c:8: warning: first argument of `main' should be `int'
junk.c:8: warning: `main' takes only zero or two arguments
junk.c: In function `main':
junk.c:7: parameter name omitted
junk.c:11: subscripted value is neither array nor pointer
junk.c:13: warning: assignment makes integer from pointer without a
cast
junk.c:13: parse error before '}' token
junk.c:14:21: warning: multi-line string literals are deprecated
junk.c:14:21: missing terminating " character
junk.c:14:21: possible start of unterminated string literal
