throw() after member function name - what for?

[k.w.]

I saw something like this:

class Fred {
public:
void g() throw();
};

What is this throw() for? I did not even know that you could put it there.
Could anyone explain this to a C++ novice?

 

[Ian Collins]

I saw something like this:

class Fred {
public:
void g() throw();
};

What is this throw() for? I did not even know that you could put it there.
Could anyone explain this to a C++ novice?

It states that the function will not throw any exceptions. The compiler
may be able to apply certain optimisations if a function only calls
others that do not throw exceptions.

 

[Alf P. Steinbach]

* k.w.:

I saw something like this:

class Fred {
public:
void g() throw();
};

What is this throw() for? I did not even know that you could put it there.
Could anyone explain this to a C++ novice?

It's an empty exception specification, saying that no exception will
ever propagate out of g().

If an attempt is made to propagate an exception out of g(), then with a
conforming compiler a special mechanism is invoked, which by default
ends up calling std::terminate.

However, you can't rely on your compiler supporting this mechanism, even
if it accepts exception specifications.

 

[k.w.]

Thanks.