trouble with or

[shawn bright]

hello there,
i am having a problem with a simple thing.

i have this ( trying to divide up a list into three more or less equal columns )
i += 1
if i == @sites.length / 3.to_i
or i == (@sites.length / 3).to_i * 2

i am getting a lot of unexpected kOR exceptions.

what am i doing wrong ?

thanks

sk

 

[Phillip Gawlowski]

i += 1
if i == @sites.length / 3.to_i or

i == (@sites.length / 3).to_i * 2

Try this.

--
Phillip "CynicalRyan" Gawlowski
http://cynicalryan.110mb.com/
http://clothred.rubyforge.org

Rule of Open-Source Programming #48:

The number of items on a project's to-do list always grows or remains
constant.

 

[Dan Zwell]

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hello there,
i am having a problem with a simple thing.

i have this ( trying to divide up a list into three more or less equal
columns )
i += 1
if i == @sites.length / 3.to_i
or i == (@sites.length / 3).to_i * 2

i am getting a lot of unexpected kOR exceptions.

what am i doing wrong ?

thanks

sk

Your problem is that "if i == @sites.length / 3.to_i" is a complete
idea, so ruby doesn't know the line is supposed to continue. You can
either add a backslash at the end of the first line, or bring "or" up a
line:

if i == @sites.length / 3.to_i or
i == (@sites.length / 3).to_i * 2

Dan Zwell
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[shawn bright]

oh, ok, i get it, thanks much gents!
sk

-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1



Your problem is that "if i == @sites.length / 3.to_i" is a complete
idea, so ruby doesn't know the line is supposed to continue. You can
either add a backslash at the end of the first line, or bring "or" up a
line:

if i == @sites.length / 3.to_i or
i == (@sites.length / 3).to_i * 2

Dan Zwell
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q7lpVZrz5kZU9CrEvI3zgug=
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