try--catch inside do...while

[AB]

Hi All,

I've got a section of code which resembles

do
{
try...........(1)
{
//do something here
}
catch(exception)
{
//handle exception
}
}
while(condition) ;

//resume execution............(2)

If the exception is not thrown, the loop continues normally. However,
when an exception is caught...the catch block is executed after which
control moves to (2) and not back to (1) as I expected.

Can anyone tell me what I'm missing out here? If it helps...I'm using
the MSVC 8.0 compiler.

 

[Victor Bazarov]

I've got a section of code which resembles

do
{
try...........(1)
{
//do something here
}
catch(exception)
{
//handle exception
}
}
while(condition) ;

//resume execution............(2)

If the exception is not thrown, the loop continues normally. However,
when an exception is caught...the catch block is executed after which
control moves to (2) and not back to (1) as I expected.

What's the "condition" if the exception is thrown?

Can anyone tell me what I'm missing out here? If it helps...I'm using
the MSVC 8.0 compiler.

It doesn't help. If you need compiler-specific information, post to
the VC++ newsgroup: 'microsoft.public.vc.language'.

V

 

[Marcus Kwok]

I've got a section of code which resembles

do
{
try...........(1)
{
//do something here
}
catch(exception)
{
//handle exception
}
}
while(condition) ;

//resume execution............(2)

If the exception is not thrown, the loop continues normally. However,
when an exception is caught...the catch block is executed after which
control moves to (2) and not back to (1) as I expected.

What happens when you run this program?


#include <iostream>

int main()
{
int i = 0;

do {
try {
std::cout << "i = " << i << '\n';
++i;
if (i == 2) {
throw 2;
}
}
catch (int e) {
std::cout << "caught " << e << '\n';
}
} while (i < 4);
}


Using MSVC 7.1 my output is:

i = 0
i = 1
caught 2
i = 2
i = 3