url fetching from xml depending upon selection

S

shanti bhushan

I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
<title>My Podcasts</title>
<dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
<dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
<TestCase name="Sprint_001">
<Input url="http://first.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_002">
<Input url="http://second.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_003">
<Input url="http://third.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
</body>
</opml>


This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

url=node.attrib.get('url')
print url



i want to print the url depending on name="sprint_001".
If i change my option to sprint_002 it should print url for sprint_002
 
S

shanti bhushan

I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
        <title>My Podcasts</title>
        <dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
        <dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
  <TestCase name="Sprint_001">
    <Input url="http://first.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_002">
    <Input url="http://second.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_003">
    <Input url="http://third.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
</body>
</opml>

This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
    tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

        url=node.attrib.get('url')
        print url

i want to print the url depending on name="sprint_001".
If i change my option to sprint_002 it should print url for sprint_002
Click to expand...

this code print all URL but there is no option to select URLs
depending upon my choice

from xml.etree import ElementTree
with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)
for node in tree.findall('.//TestCase/Input'):
url=node.attrib.get('url')
print url
 
S

shanti bhushan

I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
        <title>My Podcasts</title>
        <dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
        <dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
  <TestCase name="Sprint_001">
    <Input url="http://first.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_002">
    <Input url="http://second.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_003">
    <Input url="http://third.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
</body>
</opml>

This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
    tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

        url=node.attrib.get('url')
        print url

i want to print the url depending on name="sprint_001".
If i change my option to sprint_002 it should print url for sprint_002
Click to expand...



i am trying to do with this code
please correct my code

from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)

for node in tree.findall('.//TestCase/Input'):
if name=='Sprint_001':
print node.attrib.get('url')

i want to print only url that comes under name=Sprint_001
 
S

Stefan Behnel

shanti bhushan, 18.05.2010 07:18:
I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
<title>My Podcasts</title>
<dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
<dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
<TestCase name="Sprint_001">
<Input url="http://first.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_002">
<Input url="http://second.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_003">
<Input url="http://third.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
</body>
</opml>


This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

url=node.attrib.get('url')
print url

i want to print the url depending on name="sprint_001".
Click to expand...

for test_case in tree.findall('.//TestCase'):
if test_case.get('name') == 'sprint_002':
for input_el in test_case:
print input_el.get('url')

Stefan
 
S

shanti bhushan

I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
        <title>My Podcasts</title>
        <dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
        <dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
  <TestCase name="Sprint_001">
    <Input url="http://first.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_002">
    <Input url="http://second.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
  <TestCase name="Sprint_003">
    <Input url="http://third.co.jp" />
    <Input url="http://www.google.com" />
    <Input url="http://www.epaper.times.india.com" />
  </TestCase>
</body>
</opml>

This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
    tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

        url=node.attrib.get('url')
        print url

i want to print the url depending on name="sprint_001".
If i change my option to sprint_002 it should print url for sprint_002
Click to expand...


i have tried some new things here

from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)

for node in tree.findall('.//TestCase/'):
print node.attrib.keys()
print node.attrib.items()
print node.attrib.get(1)

url=node.attrib.get('url')
print url



but i am not getting idea ... how to achive my motive
 
S

shanti bhushan

shanti bhushan, 18.05.2010 07:18:














     for test_case in tree.findall('.//TestCase'):
         if test_case.get('name') == 'sprint_002':
            for input_el in test_case:
                print input_el.get('url')

Stefan- Hide quoted text -

- Show quoted text -
Click to expand...

Hi Stevan
i tried your logic i am not getting any out put for this
 
S

Stefan Behnel

shanti bhushan, 18.05.2010 07:18:
I have a sample.XML file
the code is like this

<?xml version="1.0" encoding="UTF-8"?>
<opml version="1.0">
<head>
<title>My Podcasts</title>
<dateCreated>Sun, 07 Mar 2010 15:53:26

GMT</dateCreated>
<dateModified>Sun, 07 Mar 2010 15:53:26

GMT</dateModified>
</head>
<body>
<TestCase name="Sprint_001">
<Input url="http://first.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_002">
<Input url="http://second.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_003">
<Input url="http://third.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
</body>
</opml>


This my python code
from xml.etree import ElementTree

with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)

for node, value in tree.findall('.//TestCase/Input'):

url=node.attrib.get('url')
print url



i want to print the url depending on name="sprint_001".
If i change my option to sprint_002 it should print url for sprint_002
Click to expand...

Actually, try this:

test_cases = dict(
(test_case.get('name'), [ el.get('url') for el in test_case ])
for test_case in tree.findall('.//TestCase') )

print test_cases['Sprint_001'] # -> prints list of URLs

That gives you a dict of test case names that are mapped to the list of
their URLs.

Stefan
 
S

shanti bhushan

shanti bhushan, 18.05.2010 07:18:














     for test_case in tree.findall('.//TestCase'):
         if test_case.get('name') == 'sprint_002':
            for input_el in test_case:
                print input_el.get('url')

Stefan- Hide quoted text -

- Show quoted text -
Click to expand...

Great Help Stefan -
my regards to you
thankyou once again it waorks fine ...
 
S

Stefan Behnel

shanti bhushan, 18.05.2010 10:08:
shanti bhushan, 18.05.2010 07:18:
>>> [...]
<body>
<TestCase name="Sprint_001">
<Input url="http://first.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_002">
<Input url="http://second.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
<TestCase name="Sprint_003">
<Input url="http://third.co.jp" />
<Input url="http://www.google.com" />
<Input url="http://www.epaper.times.india.com" />
</TestCase>
</body>
</opml>
Click to expand...
This my python code
from xml.etree import ElementTree
Click to expand...
with open('our.xml', 'rt') as f:
tree = ElementTree.parse(f)
Click to expand...
for node, value in tree.findall('.//TestCase/Input'):
Click to expand...
url=node.attrib.get('url')
print url
Click to expand...
i want to print the url depending on name="sprint_001".
Click to expand...

for test_case in tree.findall('.//TestCase'):
if test_case.get('name') == 'sprint_002':
for input_el in test_case:
print input_el.get('url')
Click to expand...
i tried your logic i am not getting any out put for this
Click to expand...

Obviously, because the correct name value is 'Sprint_002', not
'sprint_002'. Please ask back if you need help in understanding the code I
posted.

Stefan
 

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