A
asit
I have this piece of code
import urllib2
proc_url = 'http://www.nse-india.com/content/historical/EQUITIES/2001/
JAN/cm01JAN2001bhav.csv.zip'
print 'processing....', proc_url
req = urllib2.Request(proc_url)
res = urllib2.urlopen(req)
when i run this...following error comes
Traceback (most recent call last):
File "C:/Python26/reqnse.py", line 92, in <module>
res = urllib2.urlopen(req)
File "C:\Python26\lib\urllib2.py", line 124, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python26\lib\urllib2.py", line 395, in open
response = meth(req, response)
File "C:\Python26\lib\urllib2.py", line 508, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python26\lib\urllib2.py", line 433, in error
return self._call_chain(*args)
File "C:\Python26\lib\urllib2.py", line 367, in _call_chain
result = func(*args)
File "C:\Python26\lib\urllib2.py", line 516, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
would anyone help me why ??
import urllib2
proc_url = 'http://www.nse-india.com/content/historical/EQUITIES/2001/
JAN/cm01JAN2001bhav.csv.zip'
print 'processing....', proc_url
req = urllib2.Request(proc_url)
res = urllib2.urlopen(req)
when i run this...following error comes
Traceback (most recent call last):
File "C:/Python26/reqnse.py", line 92, in <module>
res = urllib2.urlopen(req)
File "C:\Python26\lib\urllib2.py", line 124, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python26\lib\urllib2.py", line 395, in open
response = meth(req, response)
File "C:\Python26\lib\urllib2.py", line 508, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python26\lib\urllib2.py", line 433, in error
return self._call_chain(*args)
File "C:\Python26\lib\urllib2.py", line 367, in _call_chain
result = func(*args)
File "C:\Python26\lib\urllib2.py", line 516, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden
would anyone help me why ??