L
loveNUNO
Hi ~
Plz Help me ~~
My problem is..
XBRL Sample file
------------------
a.xbrl
<?xml version="1.0" encoding="utf-8"?>
<group xmlns="http://www.xbrl.org/2001/instance"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:link="http://www.xbrl.org/2001/XLink/xbrllinkbase"
xmlns:xlink="http://www.w3.org/1999/xlink"
xmlns:ISO4217="http://www.iso.org/4217"
xmlns:aXinfo="http://www.love.com"
xmlns:kkw="http://www.love.com/xbrl/taxonomy"
xsi:schemaLocation="http://www.love.com/xbrl/taxonomy kkw.xsd">
<!-- PARAMETER INFO -->
<aXinfoARAMETER-INFO>
<aXinfoaram name="companyCD" value="50925"/>
.....
</aXinfoARAMETER-INFO>
<!-- ELEMENTS -->
<kkw:CRP_NM nonNumericContext="nonNumC1">cyber</kkw:CRP_NM>
<kkw:RSP_DPT nonNumericContext="nonNumC1">300</kkw:RSP_DPT>
.....
</group>
-----------------------
and xml sample
-----------------------
a.xml
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="xbrl.xsl"?>
<DOCUMENT EID="1">
.....
</DOCUMENT EID="1">
-----------------------
XSLT transform a.xml.
I used document() function.
====> <xsl:value-of select="document(a.xbrl')/group/kkw:CRP_NM" />
But it is not working.
How get I a.xbrl 's element?
Plz Help me ~~
My problem is..
XBRL Sample file
------------------
a.xbrl
<?xml version="1.0" encoding="utf-8"?>
<group xmlns="http://www.xbrl.org/2001/instance"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:link="http://www.xbrl.org/2001/XLink/xbrllinkbase"
xmlns:xlink="http://www.w3.org/1999/xlink"
xmlns:ISO4217="http://www.iso.org/4217"
xmlns:aXinfo="http://www.love.com"
xmlns:kkw="http://www.love.com/xbrl/taxonomy"
xsi:schemaLocation="http://www.love.com/xbrl/taxonomy kkw.xsd">
<!-- PARAMETER INFO -->
<aXinfoARAMETER-INFO>
<aXinfoaram name="companyCD" value="50925"/>
.....
</aXinfoARAMETER-INFO>
<!-- ELEMENTS -->
<kkw:CRP_NM nonNumericContext="nonNumC1">cyber</kkw:CRP_NM>
<kkw:RSP_DPT nonNumericContext="nonNumC1">300</kkw:RSP_DPT>
.....
</group>
-----------------------
and xml sample
-----------------------
a.xml
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="xbrl.xsl"?>
<DOCUMENT EID="1">
.....
</DOCUMENT EID="1">
-----------------------
XSLT transform a.xml.
I used document() function.
====> <xsl:value-of select="document(a.xbrl')/group/kkw:CRP_NM" />
But it is not working.
How get I a.xbrl 's element?