web server - accept() method

[Ben]

hi all,

Just trying to figure out what the accept() method in socket.py does.

Lets consider the following webserver code:

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
port = 8881
ock.bind(('',port))
....
....

while 1:
(newSock, addr) = sock.accept()
...
...

Here accept() returns newSock and addr. In my case "addr" holds the
value something like: ('127.0.0.1', 2571). What is 2571? This value
keeps changing each time i make a connection to above webserver. What
does this mean?

And also what is "newSock"? It holds value such as:
<socket object, fd=4, family=2, type=1, protocol=0>
What do i mean by this?

Thanks
Ben

 

[Guest]

Just trying to figure out what the accept() method in socket.py does.

On Unix you can check "man 2 accept", or even beter try to find the book
„UNIX Network Programming“ by Richard W. Stevens. Its a great book

Here accept() returns newSock and addr. In my case "addr" holds the
value something like: ('127.0.0.1', 2571). What is 2571? This value
keeps changing each time i make a connection to above webserver. What
does this mean?

That's the client address and port number.

And also what is "newSock"? It holds value such as:
<socket object, fd=4, family=2, type=1, protocol=0>
What do i mean by this?

newsock is a "socket", this one you use for communicating with the client.
The original socket is a listening one only...