what's wrong?

[questions]

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

printf("the result is %d",y);

return 0;}

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

 

[Kai-Uwe Bux]

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3); [snip]
The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

pow() returns a floating point (in this case, I guess a double) and x is a
long int. That is not a valid pair of operand types for the % operator.


Best

Kai-Uwe Bux

 

[Zeppe]

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

printf("the result is %d",y);

return 0;}

The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

my compiler says:

testmod.cpp:8: warning: format ‘%d’ expects type ‘int*’, but argument 2
has type ‘long int*’
testmod.cpp:10: error: invalid operands of types ‘long int’ and ‘double’
to binary ‘operator%’
testmod.cpp:12: warning: format ‘%d’ expects type ‘int’, but argument 2
has type ‘long int’

It looks pretty much clear. Listen to your compiler. It's your friend.

Best wishes,

Zeppe

 

[Juha Nieminen]

y=x%pow(10,3);

What's wrong with 1000?

 

[Kai-Uwe Bux]

What's wrong with 1000?

Nit: 1000 does not occur in the above whereas 1000.0 does occur.


Best

Kai-Uwe Bux

 

[Sjouke Burry]

Nit: 1000 does not occur in the above whereas 1000.0 does occur.


Best

Kai-Uwe Bux

Another nit : Seeing the % sign suggests that the intent is to use 1000

 

[Juha Nieminen]

Nit: 1000 does not occur in the above whereas 1000.0 does occur.

But 1000 would work, whereas 1000.0 wouldn't.

 

[Kai-Uwe Bux]

But 1000 would work, whereas 1000.0 wouldn't.

Ah, now I understand your point: you meant to replace pow(10,3) by 1000.


Sorry for the noise.

Kai-Uwe Bux

 

[questions]

# include <stdio.h>
# include <math.h>
int main()
{ long int x,y;

printf("enter an integer\n");
scanf("%d",&x);

y=x%pow(10,3);

[snip]
The compiler tell me there is something wrong with the "pow",but I
don't know what's the wrong?

pow() returns a floating point (in this case, I guess a double) and x is a
long int. That is not a valid pair of operand types for the % operator.

Best

Kai-Uwe Bux

thanks

 

[questions]

my compiler says:

testmod.cpp:8: warning: format '%d' expects type 'int*', but argument 2
has type 'long int*'
testmod.cpp:10: error: invalid operands of types 'long int' and 'double'
to binary 'operator%'
testmod.cpp:12: warning: format '%d' expects type 'int', but argument 2
has type 'long int'

It looks pretty much clear. Listen to your compiler. It's your friend.

Best wishes,

Zeppe- Òþ²Ø±»ÒýÓÃÎÄ×Ö -

- ÏÔʾÒýÓõÄÎÄ×Ö -

thanks

 

[questions]

Ah, now I understand your point: you meant to replace pow(10,3) by 1000.

Sorry for the noise.

Kai-Uwe Bux

thanks