E
EricP
I get the following error when I run this script to open a file dialog.
I've searched the web and news groups for this issue and have not found any
references. I get the same behavior when I run it from Python or Pythonwin.
I'm new to win32... and would appreciate any help I can get.
If I comment out the following line it works fine but I have to navigate to
my initial directory.....
pd.SetOFNInitialDir = r'D:\Documents and Settings\John'
# File Dialog Example
import win32ui
import win32con
pd = win32ui.CreateFileDialog(1)
pd.SetOFNInitialDir = r'D:\Documents and Settings\John'
pd.DoModal()
print 'filename =',pd.GetFileName()
print 'path =', pd.GetPathName()
pd=None
Traceback (most recent call last):
File "filedialog.py", line 4, in ?
pd.SetOFNInitialDir = 'D:\Documents and Settings\Eric'
TypeError: PyCFileDialog has read-only attributes
Also is there a way to open the XP file dialog that has the navigation
shortcuts on the left side of the dialog window?
Thanks
Eric
I've searched the web and news groups for this issue and have not found any
references. I get the same behavior when I run it from Python or Pythonwin.
I'm new to win32... and would appreciate any help I can get.
If I comment out the following line it works fine but I have to navigate to
my initial directory.....
pd.SetOFNInitialDir = r'D:\Documents and Settings\John'
# File Dialog Example
import win32ui
import win32con
pd = win32ui.CreateFileDialog(1)
pd.SetOFNInitialDir = r'D:\Documents and Settings\John'
pd.DoModal()
print 'filename =',pd.GetFileName()
print 'path =', pd.GetPathName()
pd=None
Traceback (most recent call last):
File "filedialog.py", line 4, in ?
pd.SetOFNInitialDir = 'D:\Documents and Settings\Eric'
TypeError: PyCFileDialog has read-only attributes
Also is there a way to open the XP file dialog that has the navigation
shortcuts on the left side of the dialog window?
Thanks
Eric