XSL Umformung

Sascha Kerschhofer · Jun 24, 2005

Hi,
ich suche eine Idee, wie man folgendes mit XSL erreichen kann: folgendes XML
Dokument:
<body>
Erster Text 
Zweiter Text 
Dritter Text 
Vierter Text 

Fünfter Text 

Sechster Text
</body>

Ich will das nun in einzelne Absätze teilen, aber so, dass der Text im
Absatz es immer "kumulativ" wird außer clear-previous ist true (die übrigen
Formatierungen müssen aber erhalten bleiben). Das würde liefern:

<body>
Erster Text
Erster TextZweiterText
Erster TextZweiterTextDritter Text
Vierter Text
Vierter TextFünfter Text
Vierter TextFünfter TextSechster Text
</body>

Hat jemand eine Idee oder Lösung?

Sascha Kerschhofer

Sascha Kerschhofer · Jun 24, 2005

Sorry, wrong Newsgroup selected...

Joris Gillis · Jun 26, 2005

Ich will das nun in einzelne Absätze teilen, aber so, dass der Text im
Absatz es immer "kumulativ" wird außer clear-previous ist true (die
übrigen
Formatierungen müssen aber erhalten bleiben). Das würde liefern:

Hi,

Here you find a working solution.
It uses a combination of a key method and a recursivly called template.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl

utput method="xml" indent="yes"/>

<xsl:key name="before_br" match="node()[not(self::br)]"
use="generate-id(following-sibling::br[1])"/>

<xsl:template match="body">
<xsl:copy>
<xsl:apply-templates select="br"/>
<xsl:if test="br[last()]/following-sibling::node()">

<xsl:apply-templates select="br[last()]" mode="copy_tail"/>
<xsl:copy-of select="br[last()]/following-sibling::node()"/>

</xsl:if>
</xsl:copy>
</xsl:template>

<xsl:template match="br">

<xsl:if test="not(@clear-previous='true')">
<xsl:apply-templates select="preceding-sibling::br[1]"
mode="copy_tail"/>
</xsl:if>
<xsl:copy-of select="key('before_br',generate-id())"/>

</xsl:template>

<xsl:template match="br" mode="copy_tail">
<xsl:apply-templates select="preceding-sibling::br[1]" mode="copy_tail"/>
<xsl:copy-of select="key('before_br',generate-id())"/>
</xsl:template>

<xsl:template match="br[@clear-previous='true']" mode="copy_tail">
<xsl:copy-of select="key('before_br',generate-id())"/>
</xsl:template>

</xsl:stylesheet>

regards,

Sascha Kerschhofer · Jun 28, 2005

Thank you Joris,
this works pretty well. Honestly this is a quite interesting but however a
guru-stylesheet and I don't understand exactly how it works. What is the
recursion-rule? Maybe there is a chance to get it explained

.
Unfortunately I had made a mistake in my example since the "new" text group
must be started after a br[@clear-previous="true"]. The example below is
corrected now. So what need to be modified?

For all not-german speaking people here is the actual question:

I need to transform some text that is divided by empty br-elements into
separate paragraphs. Further all separated text fragments must be
progressively collected. Example:

<body>
First Text 
Second Text 
Thrird Text 
Fourth Text 
Fifth Text 
Sixt Text
</body>

becomes

<body>
First Text
First TextZweiter Text
First TextSecond TextThird Text
First TextSecond TextThird TextFourth Text
Fitht Text
Fith TextSixt Text
</body>

Sascha Kerschhofer

Joris Gillis · Jun 28, 2005

Hi,

On Tue, 28 Jun 2005 14:28:54 +0200, Kerschhofer Alexander

Honestly this is a quite interesting but however a guru-stylesheet
It would take a guru to code a guru-stylesheet

Mine was probably
unintelligable...
and I don't understand exactly how it works. What is the recursion-rule?
The recursion is done via the 'copy_tail' template
Maybe there is a chance to get it explained

.
see the comments below
Unfortunately I had made a mistake in my example since the "new" text group
must be started after a br[@clear-previous="true"]. The example below is
corrected now. So what need to be modified?

In that case it becomes much easier, it was actually the error in your
sample data that made the job challenging.
Here you have a new stylesheet with comments included:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl

utput method="xml" indent="yes"/>

<xsl:key name="before_br" match="node()[not(self::br)]"
use="generate-id(following-sibling::br[1])"/>


<xsl:template match="body">
<xsl:copy>
<xsl:apply-templates select="br"/>
<xsl:if test="br[last()]/following-sibling::node()">


<xsl:apply-templates select="br[last()]" mode="copy_tail"/>
<xsl:copy-of select="br[last()]/following-sibling::node()"/>

</xsl:if>
</xsl:copy>
</xsl:template>

<xsl:template match="br">

<xsl:apply-templates select="." mode="copy_tail"/>


</xsl:template>

<xsl:template match="br" mode="copy_tail">

<xsl:apply-templates
select="preceding-sibling::br[1][not(@clear-previous='true')]"
mode="copy_tail"/>
<xsl:copy-of select="key('before_br',generate-id())"/>
</xsl:template>

</xsl:stylesheet>

regards,

Sascha Kerschhofer · Jun 28, 2005

Wow, so you are indeed a guru xsl-transformer...
Sascha

Joris Gillis · Jun 28, 2005

Wow, so you are indeed a guru xsl-transformer...
I actually meant to say that I do not consider myself a guru at all.

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XSL Umformung

Sascha Kerschhofer

Sascha Kerschhofer

Joris Gillis

Sascha Kerschhofer

Joris Gillis

Sascha Kerschhofer

Joris Gillis

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