EOF question

[CBFalconer]

.... snip ...

It could be a bug in Windows and/or the C runtime.

Change the printf() line to read:

printf("aefore newline\nafter newline %ld\n",nc);

On Windows 98, with MSVC 6.0a (compiler version 12.00.8168) typing
"foobar" newline Ctrl-Z newline, I get:

foobar
after newline 7

Note that everything in the printf() prior to the newline is gone.

On Windows XP:

foobar
^Z
before newline
after newline 7

And the program has not yet exited. I need to press Enter one
more time to get the program to exit.

It's not W98 FE. Under that, and DJGPP 2.03, gcc 3.3.1:

[1] c:\c\junk>gcc junk.c

[1] c:\c\junk>a
Bloody nonsense
^Z
16

[1] c:\c\junk>type junk.c
#include <stdio.h>

int main(void)
{
long nc;

nc = 0;
while (getchar() != EOF) ++nc;
printf("%ld\n", nc);
return 0;
}

 

[newby2c]

It could be a bug in Windows and/or the C runtime.

Change the printf() line to read:

printf("aefore newline\nafter newline %ld\n",nc);

On Windows 98, with MSVC 6.0a (compiler version 12.00.8168) typing
"foobar" newline Ctrl-Z newline, I get:

foobar
after newline 7

Note that everything in the printf() prior to the newline is gone.

On Windows XP:

foobar
^Z
before newline
after newline 7

And the program has not yet exited. I need to press Enter one more time
to get the program to exit.

I get the same results as you except the program terminates after <ctrl-z>.

newby2c