suggestion for writing a program to concatanate two strings

[Artie Gold]

vire wrote:

[failing to quote the relevant portions of the post to which he/she
was responding]

#include <stdio.h>
#include <string.h>

char* getCat(char* str1,char* str2)
{
int i=strlen(str1)+strlen(str2);

BZZZZT! And the terminating null character goes where?
ITYM:
int i = strlen(str1) + strlen(str2);

I fail to see any meaningful difference. I think you meant to add a one

Ack! Of course!!!!!

in there. Also, the variable should be of type size_t.



That will require that you #include <stdlib.h>, which I didn't see you
mention.

....and some nights I *should* go to bed early...

;-(
--ag

 

[Mark McIntyre]

Thank you.
I want to write code with out using string handling functions.
So i wrote the code like that.
Now i just want to return it to tha main function.
once again thanks

 

[Emmanuel Delahaye]

vire a écrit :

char* ret= new char(i);

OMG !

 

[pete]

I want to write code with out using string handling functions.

/* BEGIN new.c */

#include <stdio.h>

char *string_concatenate(char *s1, char *s2);
char *str_cpy(char *s1, const char *s2);
size_t str_len(const char *s);

int main(void)
{
char s1[sizeof "concatenate string"] = "concatenate ";
char s2[] = "string";
char *p;

p = string_concatenate(s1, s2);
puts(p);
return 0;
}

char *string_concatenate(char *s1, char *s2)
{
str_cpy(str_len(s1) + s1, s2);
return s1;
}

size_t str_len(const char *s)
{
size_t n;

for (n = 0; *s != '\0'; ++s) {
++n;
}
return n;
}

char *str_cpy(char *s1, const char *s2)
{
char *const p1 = s1;

do {
*s1++ = *s2;
} while (*s2++ != '\0');
return p1;
}

/* END new.c */

 

[Michael Mair]

/* BEGIN new.c */

#include <stdio.h>

char *string_concatenate(char *s1, char *s2);

^
As I am sure you know the gospel, I am just curious: Why?

<snip: code at usual pete quality>

Cheers
Michael

 

[pete]

^
As I am sure you know the gospel, I am just curious: Why?

I copied it from sravishnu's original post
without thinking hard enough.